- - The original note follows - -
From: Dillon J Lin <dl4u+@xxxxxxxxxxxxxx>
Subject: Re: Golden cut (?)
Date: Thu, 8 Sep 1994 10:46:31 -0400
Do you mean a Golden Section? A golden section is the length of a
golden rectangle. The golden rectangle can be divided into a square and
another golden rectangle.
A Golden section can be constructed quite easily. There are three
important points in a golden section labelled A, B, and C with C lying
between A and B (see fig.1)
A C B
------------------
The proportion is such that AC/AB = CB/AC
To find the location of C based on a given segment AB find the
mid-point of AB called M
A M B
---------------------
Construct a sement equal to length MB and perpendicular to B, call it BD
A M B
--------------------
|
|
|
|
|D
Now connect A and D, take a compass and draw an arc with center D
and passing through B. Swing the arc so it intersects AD, call the
intersection E. Now draw another arc with center at A and passing
through E. Swing that so it intersects AB and that intersection will be
C.
There is a construction for finding B given AC but I don't know it
off the top of my head.
_________________________________________________________________________
Dillon Jung Lin
dl4u+@xxxxxxxxxxxxxx
Carnegie Mellon University Architecture
_|_ _|_
/|\ /|\
_________________________________________________________________________
From: Dillon J Lin <dl4u+@xxxxxxxxxxxxxx>
Subject: Re: Golden cut (?)
Date: Thu, 8 Sep 1994 10:46:31 -0400
Do you mean a Golden Section? A golden section is the length of a
golden rectangle. The golden rectangle can be divided into a square and
another golden rectangle.
A Golden section can be constructed quite easily. There are three
important points in a golden section labelled A, B, and C with C lying
between A and B (see fig.1)
A C B
------------------
The proportion is such that AC/AB = CB/AC
To find the location of C based on a given segment AB find the
mid-point of AB called M
A M B
---------------------
Construct a sement equal to length MB and perpendicular to B, call it BD
A M B
--------------------
|
|
|
|
|D
Now connect A and D, take a compass and draw an arc with center D
and passing through B. Swing the arc so it intersects AD, call the
intersection E. Now draw another arc with center at A and passing
through E. Swing that so it intersects AB and that intersection will be
C.
There is a construction for finding B given AC but I don't know it
off the top of my head.
_________________________________________________________________________
Dillon Jung Lin
dl4u+@xxxxxxxxxxxxxx
Carnegie Mellon University Architecture
_|_ _|_
/|\ /|\
_________________________________________________________________________